How tall is Jelena Janković?
Serbian tennis player
By Nitin Raja · Software developer, founder of CheckMyHeight
· 2 min read · Heights from Wikidata · How we check heights
Jelena Janković is 5′ 9½″ tall - that's 177 cm or 69.7 inches.
Averages are for US adults (CDC NHANES).
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Jelena Janković compared with the average in Serbia
The average young woman in Serbia is 5′ 6½″ (168.3 cm) at age 19, according to the NCD Risk Factor Collaboration (2019). At 5′ 9½″, Jelena Janković is 8.7 cm taller than that, and 16.1 cm taller than the world average for young women (5′ 3½″).
In the athletes list, Jelena Janković ranks 386th of 553 by height.
Same height as Jelena Janković
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Jelena Janković height comparison
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Jelena Janković height FAQ
How tall is Jelena Janković?
Jelena Janković is 5′ 9½″ tall, which is 177 cm or 69.7 inches.
How tall is Jelena Janković in cm?
Jelena Janković's height is 177 cm (1.77 m).
Is Jelena Janković taller than average?
Yes - the average American woman is 5′ 3½″ (161.3 cm), so Jelena Janković is 15.7 cm taller, taller than about over 99% of US women.
How much does Jelena Janković weigh?
Jelena Janković weighs about 59 kg (130 lb) according to Wikidata - at 5′ 9½″ that's a BMI of 18.8. Weights change more than heights, so treat it as approximate.
How tall is Jelena Janković compared with the average person in Serbia?
The average young woman in Serbia is 5′ 6½″ (168.3 cm) at age 19 (NCD-RisC, 2019). At 5′ 9½″, Jelena Janković is 8.7 cm taller.
Who is the same height as Jelena Janković?
J-Hope, Robert De Niro, Jack Nicholson, Sylvester Stallone are also listed at about 5′ 9½″.
Source: Wikidata (Q15269). Celebrities often round up or are measured in shoes, so treat this as within a centimetre or two.