How tall is Justine Henin?
Belgian tennis player (born 1982)
By Nitin Raja · Software developer, founder of CheckMyHeight
· 2 min read · Heights from Wikidata · How we check heights
Justine Henin is 5′ 5½″ tall - that's 167 cm or 65.7 inches.
Averages are for US adults (CDC NHANES).
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Justine Henin compared with the average in Belgium
The average young woman in Belgium is 5′ 4½″ (163.4 cm) at age 19, according to the NCD Risk Factor Collaboration (2019). At 5′ 5½″, Justine Henin is 3.6 cm taller than that, and 6.1 cm taller than the world average for young women (5′ 3½″).
In the athletes list, Justine Henin ranks 540th of 553 by height.
Same height as Justine Henin
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Justine Henin height comparison
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Justine Henin height FAQ
How tall is Justine Henin?
Justine Henin is 5′ 5½″ tall, which is 167 cm or 65.7 inches.
How tall is Justine Henin in cm?
Justine Henin's height is 167 cm (1.67 m).
Is Justine Henin taller than average?
Yes - the average American woman is 5′ 3½″ (161.3 cm), so Justine Henin is 5.7 cm taller, taller than about 79% of US women.
How much does Justine Henin weigh?
Justine Henin weighs about 57 kg (126 lb) according to Wikidata - at 5′ 5½″ that's a BMI of 20.4. Weights change more than heights, so treat it as approximate.
How tall is Justine Henin compared with the average person in Belgium?
The average young woman in Belgium is 5′ 4½″ (163.4 cm) at age 19 (NCD-RisC, 2019). At 5′ 5½″, Justine Henin is 3.6 cm taller.
Who is the same height as Justine Henin?
Volodymyr Zelenskyy, Aishwarya Rai, Priyanka Chopra, Pamela Anderson are also listed at about 5′ 5½″.
Source: Wikidata (Q11682). Celebrities often round up or are measured in shoes, so treat this as within a centimetre or two.